Question

The reaction below has an equilibrium constant of Kp=2.26×104 at 298 K.
CO(g)+2H2(g)⇌CH3OH(g)

A) Calculate Kp for the reaction below.
12CH3OH(g)⇌12CO(g)+H2(g)

B) Calculate Kp for the reaction below.
2CO(g)+4H2(g)⇌2CH3OH(g)

C) Calculate Kp for the reaction below.
3CH3OH(g)⇌3CO(g)+6H2(g)

Answer 1

A)

reaction givev is not balanced

It will be

12CH3OH(g)⇌12CO(g)+24H2(g)

It can be obtained from original given reaction by reversing and then multiplying it by 12

Kp’ = (1/kp)^12

   = (1/(2.26*10^4))^12

=5.63*10^-53

B)

It can be obtained from original given reaction by multiplying it by 2

Kp’ = (kp)^2

   = (2.26*10^4)^2

=5.11*10^8

C)

It can be obtained from original given reaction by reversing and then multiplying it by 3

Kp’ = (1/kp)^3

   = (1/(2.26*10^4))^3

=8.66*10^-14