Question

Suppose a reaction with a single reactant is first order in that reactant. As a first-order...

Suppose a reaction with a single reactant is first order in that reactant. As a first-order reaction, the concentration of the reactant will decrease exponentially with time, and its half-life will be constant. Does the fraction of molecules that react per unit time change as the reaction progresses? Justify your answer.

please justify with words and not just equations.

Homework Answers

Answer #1

Does not change

Explanation

For first order reaction

t1/2 = 0.693/k

where, k is rate constant

so,

rate constant, k = 0.693/t1/2

Integrated form first order equation is

ln[A]t = -kt + ln[A0]

where,

[A]0 = Initial concentration of reactant

[A]t = Concentration at time t

ln([A]0/[A]t) = kt

half life is not changing,

so, at half life

ln([A]0/[A]t) = kt1/2

the term, kt1/2 = constant

Therefore,

[A]0/[A]t = Constant

the ratio between Concentration A at initial and Concentration of A at half life is not changing

Therefore,

Fraction of molecules that react per unit time will not change

as the reaction progress

  

     

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a first-order reaction, the half-life is constant. It depends only on the rate constant k...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2=0.693k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0 Part A A certain first-order reaction (A→products) has a rate constant of 4.20×10−3 s−1 at 45 ∘C. How many minutes does it take for the concentration of the reactant, [A],...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2=0.693k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0 Part A A certain first-order reaction (A→products ) has a rate constant of 5.10×10−3 s−1 at 45 ∘C . How many minutes does it take for the concentration of the...
The reaction A→C is first-order in the reactant A and is known to go to completion....
The reaction A→C is first-order in the reactant A and is known to go to completion. The product C is colored and absorbs light strongly at 550 nm, while the reactant and intermediates are colorless. A solution of A was prepared, and the absorbance of C at 550 nm was measured as a function of time. (Note that the absorbance of C is directly proportional to its concentration.) Use the following data to determine the half-life of the reaction: Time...
For a particular first-order reaction, it takes 48 minutes for the concentration of the reactant to...
For a particular first-order reaction, it takes 48 minutes for the concentration of the reactant to decrease to 25% of its initial value. What is the value for rate constant (in s-1) for the reaction? Select one: A. 4.8 × 10-4 s-1 B. 6.0 × 10-3 s-1 C. 1.0 × 10-4 s-1 D. 2.9 × 10-2 s-1 For the first-order reaction, 2 N2O(g) → 2 N2(g) + O2(g), what is the concentration of N2O after 3 half-lives if 0.15 mol...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its inital value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation caculates the time...
Part A : A certain first-order reaction (A→products) has a rate constant of 9.30×10−3 s−1 at...
Part A : A certain first-order reaction (A→products) has a rate constant of 9.30×10−3 s−1 at 45 ∘C. How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration? Part B : A certain second-order reaction (B→products) has a rate constant of 1.10×10−3M−1⋅s−1 at 27 ∘C and an initial half-life of 278 s . What is the concentration of the reactant B after one half-life?
Part A Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ...
Part A Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K . Part B Calculate this fraction for a temperature of 524 K . Part C What is the ratio of the fraction at 524 K to that at 510 K ? Part A What is the half-life of a first-order reaction with a rate constant of 7.20×10−4  s−1? Part B What is the rate constant of a first-order reaction that...
What is the half-life of a first-order reaction with a rate constant of 4.20×10−4  s−1? (the answer...
What is the half-life of a first-order reaction with a rate constant of 4.20×10−4  s−1? (the answer is 1650s) What is the rate constant of a first-order reaction that takes 458 seconds for the reactant concentration to drop to half of its initial value?
1A. For a first order reaction, the rate will double if a.      Concentration of a reactant...
1A. For a first order reaction, the rate will double if a.      Concentration of a reactant is doubled b.     Concentration of a product is doubled c.      Concentration of a reactant is squared d.     Temperature is raised two degrees e.    2 moles of catalyst are added 1B.     For a second order decomposition reaction (one reactant), if the concentration of the reactant is tripled, the rate: a.      Triples b.     Increases nine-fold c.      Decreases by one third d.     Stays the same