Question

Please answer the following questions:

1) Balance this equation: ____ LiOH + ____ Fe(NO3)3 --> ____ LiNO3 + ____ Fe(OH)3

2) What type of chemical reaction is taking place in this process?

3) If I perform this reaction by combining 25.0g of LiOH with an excess of Fe(NO3)3, how much Fe(OH)3 will I be able to make?

4) If 47.5g of Fe(OH)3 are actually made, what is my percent yield for this reaction?

****Having a hard time solving this, would you be able to break down the steps in solving these equations? THANK YOU :)

Answer 1

1)

Balanced chemical equation is:

3 LiOH + Fe(NO3)3 --> 3 LiNO3 + Fe(OH)3

2)

This is double displacement reaction

3)

mass of LiOH = 25.0 g

molar mass of LiOH = 24 g/mol

mol of LiOH = (mass)/(molar mass)

= 25/24

= 1.042 mol

According to balanced equation

mol of Fe(OH)3 formed = (1/3)* moles of LiOH

= (1/3)*1.042

= 0.347 mol

mass of Fe(OH)3 = number of mol * molar mass of Fe(OH)3

= 0.347*106.9

= 37.1 g

Answer: 37.1 g

4)

% yield = actual mass*100/theoretical mass

= 47.5*100/37.1

= 128 %

Answer: 128 %