Question

(Part A) For the reaction, calculate how many grams of the product form when 16.4 g...

(Part A) For the reaction, calculate how many grams of the product form when 16.4 g of O2 completely reacts.
Assume that there is more than enough of the other reactant.
4Cr(s)+3O2(g)→2Cr2O3(s)

(Part B) For the reaction, calculate how many grams of the product form when 16.4 g of Sr completely reacts.
Assume that there is more than enough of the other reactant.
2Sr(s)+O2(g)→2SrO(s)

Homework Answers

Answer #1

A)

mass of O2 = 16.4 g
molar mass of O2 = 32 g/mol
mol of O2 = (mass)/(molar mass)
= 16.4/32
= 0.5125 mol


According to balanced equation
mol of Cr2O3 formed = (2/3)* moles of O2
= (2/3)*0.5125
= 0.341667 mol



mass of Cr2O3 = number of mol * molar mass
= 0.341667*152
= 51.9 g
Answer: 51.9 g

B)

mass of Sr = 16.4 g
molar mass of Sr = 87.62 g/mol
mol of Sr = (mass)/(molar mass)
= 16.4/87.62
= 0.187172 mol

According to balanced equation
mol of SrO formed = moles of Sr
= 0.187172 mol



mass of SrO = number of mol * molar mass
= 0.187172*103.62
= 19.4 g
Answer: 19.4 g

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
(Part A) For the reaction, calculate how many grams of the product form when 16.4 g...
(Part A) For the reaction, calculate how many grams of the product form when 16.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant. Ca(s)+Cl2(g)→CaCl2(s) (Part B) For the reaction, calculate how many grams of the product form when 16.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant. 2K(s)+Br2(l)→2KBr(s)
For the reaction, calculate how many grams of the product form when 24.4 g of O2...
For the reaction, calculate how many grams of the product form when 24.4 g of O2 completely reacts. Assume that there is more than enough of the other reactant. 4Cr(s)+3O2(g)→2Cr2O3(s)
For the reaction, calculate how many moles of the product form when 0.046 mol of O2...
For the reaction, calculate how many moles of the product form when 0.046 mol of O2 completely reacts. Assume that there is more than enough of the other reactant. 2Ca(s)+O2(g)→2CaO(s) For the reaction, calculate how many moles of the product form when 0.018 mol of O2 completely reacts. Assume that there is more than enough of the other reactant. 4Fe(s)+3O2(g)→2Fe2O3(s) For the reaction, calculate how many moles of the product form when 0.044 mol of K completely reacts. Assume that...
For the reaction below, calculate how many moles of the product form when 0.026 mol of...
For the reaction below, calculate how many moles of the product form when 0.026 mol of O2 completely reacts. Assume that there is more than enough of the other reactant. 2Ca(s)+O2(g)→2CaO(s) Express your answer using two significant figures.
For each of the reactions, calculate the mass (in grams) of the product formed when 15.82...
For each of the reactions, calculate the mass (in grams) of the product formed when 15.82 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant. Express your answer using four significant figures. 1) 2K(s)+Cl2(g)−−−−−→2KCl(s) 2) 2K(s)+Br2(l)−−−−−→2KBr(s) 3) 4Cr(s)+3O2(g)−−−−−→2Cr2O3(s)
For each of the reactions, calculate the mass (in grams) of the product formed when 3.30...
For each of the reactions, calculate the mass (in grams) of the product formed when 3.30 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant. (underlined) Ba(s)?????+Cl2(g)?BaCl2(s) (underlined) CaO(s)??????+CO2(g)?CaCO3(s) (underlined) 2Mg(s)?????+O2(g)?2MgO(s)   (underlined) 4Al(s)?????+3O2(g)?2Al2O3(s)
For each of the reactions, calculate the mass (in grams) of the product formed when 3.33...
For each of the reactions, calculate the mass (in grams) of the product formed when 3.33 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant. 1. Ba(s)+Cl2(g)→BaCl2(s) 2. CaO(s)+CO2(g)→CaCO3(s) 3. 2Mg(s)+O2(g)→2MgO(s) 4. 4Al(s)+3O2(g)→2Al2O3(s)
CaO(s)−−−−−−+CO2(g)→CaCO3(s) Express your answer using two significant figures. For each reaction, calculate the mass (in grams)...
CaO(s)−−−−−−+CO2(g)→CaCO3(s) Express your answer using two significant figures. For each reaction, calculate the mass (in grams) of the product formed when 2.9 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant. Ba(s)−−−−−+Cl2(g)→BaCl2(s) Express your answer using two significant figures. 2Mg(s)−−−−−+O2(g)→2MgO(s) Express your answer using two significant figures. 4Al(s)−−−−−+3O2(g)→2Al2O3(s) Express your answer using two significant figures.
grams A to moles A to moles B to grams B 2 C4H10 (l) + 13...
grams A to moles A to moles B to grams B 2 C4H10 (l) + 13 O2(g) --> 8 CO2(g) + 10 H2O(g) How many moles of each product will form if 8.12 g of butane (C4H10) reacts completely to form products? Assume there is more than enough of the other reactant. How many grams of CO2 will form?
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant...
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts. 2N2O5(g)→4NO2(g)+O2(g) a. 6.4 mol N2O5 b. 10.0 g N2O5 c. 1.55 kg N2O5
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT