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calculate the pH of 75mL of the undiluted buffer solution (buffer solution prepared by mixing 100mL...

calculate the pH of 75mL of the undiluted buffer solution (buffer solution prepared by mixing 100mL 1.060 M acetic acid with 100 mL 1.068 M sodium acetate solution) after the addition of 1 mL of 3 M NaOH

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Answer #1

The initial buffer pH is

pH = pKa + log[base]/[acid] = 4.750 + log (1.068/1.060) = 4.753

   

The initial quantities are

0.100L x 1.060 mol/L = 0.1060 mol acetic acid

0.100L x 1.068 mol/L = 0.1068 mol sodium acetate

0.001L x 3mol/L = 0.0030 mol NaOH added

The new pH will be

pH = pKa + log[base]/[acid] = 4.750 + log [(0.1068+0.0030)/(0.1060-0.0030)] =

       = 4.750 + log(0.1098/0.1030)

      = 4.750 + 0.028 = 4.778

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