Question

For the chemical reaction below, determine the amount of HI produced when 3.35 g of hydrogen...

For the chemical reaction below, determine the amount of HI produced when 3.35 g of hydrogen is reacted with 50.75 g of iodine to produce hydrogen iodide (HI).

H2(g) + I2(g) → 2HI(g)

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Answer #1

you need to calculate the moles of H2 and I2 so:

H2 has a molar mass of 2

moles of H2 = 3.35 / 2 = 1.675 moles

I2 has a molar mass of 253.8

moles = mass / molar mass = 50.75 / 253.8 = 0.2 moles

with this information we know that the I2 is the limiting reactant

according to the given reaction

1 mole of I2 produces 2 moles of HI so you will have 2 * 0.2 = 0.4 moles of HI

molar mass of HI is 127.9

to find the mass use:

mass = moles * molar mass

mass = 0.4 * 127.9 = 51.16 grams

*hope it helps =)

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