Consider the following reaction: |
Part A 310 K
|
ΔH∘ = ΔH∘products - ΔH∘ reactants
= (-635.1 -393.5) - (-1207)
= 178.4 kJ /mol
ΔS∘ = ΔS∘products - ΔS∘reactants
= (39.75 + 213.6)-(88.70)
= 164.65 J / K
= 0.16465 kJ / mol
at 310 K
ΔG∘ = ΔH∘ - T ΔS∘
= 178.4 - 310 x 0.16465
= 127.4 kJ / mol
at 1035 K
ΔG∘ = ΔH∘ - T ΔS∘
= 178.4 - 1035 x 0.16465
= 7.987 kJ / mol
at 1455 K
ΔG∘ = ΔH∘ - T ΔS∘
= 178.4 - 1455 x 0.16465
= - 61.17 kJ / mol
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