Question
If 3.403 g KOH are dissolved in 100.327 g H2O and the temperature increases by 4.28...
If 3.403 g KOH are dissolved in 100.327 g H2O and the temperature increases by 4.28 oC, the enthalpy of dissolution of KOH in water is ___ kJ/mol. Assume the specific heat of the resulting KOH solution is 4.18 J g-1oC-1.
Homework Answers
Answer #1
total mass of the solution = 3.403 + 100.327 = 103.73g
T =
4.280C
q = mcT
= 103.73*4.18*(4.28) = 1855.77J = 1.85577KJ
no of moles of KOH = 3.403/56 = 0.06 moles
q = 1.85577KJ/0.06 moles = 30.93KJ/mole >>>>>answer
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