A solution of 10-3-mole of sodium propionate (CH3CH2COONa) is added to 1 liter of distilled water. If the pKa = 4.87 for propionic acid, what the solution pH? Solve the appropriate equations analytically and graphically and compare the results. Also, using the same graph determine the pH if a 10-3-mole of propionic acid (CH3CH2COOH) were added instead of the sodium propionate.
Step by step explanations would be appreciated. Thanks!
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