Question

An electron traveling at 2.8×105 has an uncertainty in its velocity of 1.26×105 . What is the uncertainty in its position?

Answer 1

Use this equation to solve:

[Delta(x)]x[(m)(Delta(v)] > h / 4pi (you can more or less ignore the > symbol when solving)

Delta x stands for uncertainty in position

Delta v stands for uncertainty in velocity

m stands for mass

h is planck's constant

To solve for Delta(x), just divide each side by m and Delta(v), plug in the numbers and solve.

SO you will have h / (4pi)(m)(Delta(v))

Plug in your values

6.626x10^-34 / (4pi)(9.11x10^-31)(1.26x10^5)

= 4.5936 x10^-10 m