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A Botle of isopropyl alcohol in water is reported as being 705 30% isopropyl alcohol/water volume/volume...

A Botle of isopropyl alcohol in water is reported as being 705 30% isopropyl alcohol/water volume/volume (v/v). The density of this solution is 0.878g/mL. The density of water is 1.00g/ml

What must be the density of pure isopropyl alcohol

If the molar mass of isopropyl alcohol is 601g/mol what is the concentration in molarity

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Answer #1

705 30% isopropyl alcohol/water volume/volume means that 705 ml of the solution contains ml isopropyl alcohol and mL water.

The density of water is 1.00 g/ml

Hence, 493.5 mL of water also corresponds to 493.5 g of water.

The density of the solution is 0.878 g/ml. The mass of 705 ml of the solution is

Hence, the mass of isopropanol present in water is g

The density of isopropyl alcohol is

The molar mass of isopropanol is 60.1 g/mol

The number of moles of isopropanol present in 125.5 g are

The molarity of the solution is

Hence, the molarity if isopropanol is 1.5 M.

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