What is the final concentration of methyl red if:
A 0.05% solution of methyl red is prepared by dissolving 0.025 g in 20 mL of 95% ethanol in a 50- mL volumetric flask. Water is then added to within a few mL of the mark. ~0.1 M NaOH is added dropwise until all the solid dissolves and then diluted to the mark. 20 mL of this solution is then transfered into 50 mL of 95% ethanol in a 200 mL volumetric flask. This is then diluted to the mark with water.
We start with a 0.05% methyl red solution and dilute to prepare a final solution having volume 200 mL. 20 mL of 0.05% methyl red solution was used to prepare the dilute solution. We are required to find the concentration of methyl red in the final solution.
Use the dilution equation:
C1*V1 = C2*V2 where C1 = concentration of stock methyl red = 0.05%; V1= volume of stock methyl red solution taken = 20 mL and V2 = final volume of the dilute solution = 200 mL. Therefore,
(0.05%)*(20 mL) = C2*(200 mL)
====> C2 = (0.05%*20)/(200) = 0.005%
The final concentration of the dilute methyl red solution is 0.005% (ans).
Get Answers For Free
Most questions answered within 1 hours.