Question

How many moles of lithium carbonate do you have if you have 300 mL of a 0.4563 M solution?

Answer 1

Solution :-

We are given with molarity and volume

Volume = 300 ml * 1 L / 1000 ml = 0.300 L

Molarity = 0.4563 M

Moles of lithium carbonate = ?

Using the molarity and volume we can find the moles as follows

Molarity = moles / volume in liter

Moles = molarity x volume in liter

Moles of lithium carbonate = 0.4563 mol per L * 0.300 L

                                                 = 0.1369 mol

Therefore we have 0.1369 moles of lithium carbonate