Question

Determine the pH of each of the following solutions.

Part A:

8.23×10^{−2} M HClO4

Express your answer to three decimal places.

Part B:

A solution that is 4.8×10^{−2} M in HClO4 and
5.0×10^{−2} M in HCl

Express your answer to two decimal places.

Part C:

A solution that is 1.04% HCl by mass (Assume a density of 1.01 g/mL for the solution.)

Answer #1

PartA

HClO4 is strong acid and completely dissociates into ions

HClO4 <-------> H^{+} + ClO4^{-}

[HClO4] =
8.23×10^{-2}M

pH = -log[H^{+}]

pH = -log(8.23×10^{-2})

pH = 1.08

Part B

HClO4 and HCl both strong acid , so completely dissociates

[HClO4] = 4.8 ×10^{-2}M

[H^{+}] from HClO4 = 4.8 ×10^{-2}M

[HCl] = 5.0×10^{-2}M

[H^{+}] from HCl= 5.0 ×10^{-2}M

Total [H^{+} ]= 4.8×10^{-2}M +
5.0×10^{-2}M = 9.8×10^{-2}M

pH = -log(9.8 ×10^{-2})

pH = 1.01

Part C

Consider 1L of solution

mass of HCl = 1000ml × 1.01g/ml = 1010g

mass of HCl = (1.04/100)×1010g = 10.504g

Number of moles = mass/molar mass

number of moles of HCl = 10.504g/36.46g/mol = 0.2881mol

molarity = number of moles of solute per liter of solution

molarity of HCl = 0.2881M

molarity of H^{+} = 0.2881M

pH = -log(0.2881)

pH = 0.54

find pH - answers and work please
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Express your answer to two decimal places.
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Part B
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Express your answer to three decimal places.
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Part C
a solution that is 5.2×10−2 M in HClO4 and
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Express your answer to two decimal places.
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Part D
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Express your answer using two decimal places.
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Part B
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Express your answer using three decimal places.
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Express your answer to two decimal places.
Part B
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Part C
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