Question

Consider the reaction: 2SO2(g)+O2(g)→2SO3(g). If 288.7 mL of SO2 reacts with 150.7 mL of O2 (both...

Consider the reaction: 2SO2(g)+O2(g)→2SO3(g). If 288.7 mL of SO2 reacts with 150.7 mL of O2 (both measured at 312 K and 77 mbar) What is the theoretical yield of SO3?

Homework Answers

Answer #1

Volume of SO2 = 288.7 mL = 0.2887L

VOlume of O2 = 150.7 mL = 0.1507 L

Temperature (T) = 312K

Pressure (P) = 77 mbar =0.07599 atm

Gas constant (R) = 0.0820 L.atm/mol.K

Ideal gas equation is

PV = nRT

Moles of SO2 are

n = 0.07599 atm * 0.2887L / ( 0.0820 L.atm/mol.K * 312K) = 8.57*10-4 mol

Moles of O2

n = 0.07599 atm * 0.1507L / ( 0.0820 L.atm/mol.K * 312K) = 4.47 *10-4 mol

NOw, reaction is :

2 SO2 +    O2 2 SO3

2 mol 1 mol 2 mol

Thus, 8.57*10-4 mol of SO2 reacts with 8.57*10-4 mol/2 = 4.28 * 10-4 mol of O2

So, SO2 is a limiting reagent.

From reaction

2 mol of SO2 gives 2 mol of SO3

Thus, 8.57*10-4 mol of SO2 gives 8.57*10-4 mol of SO3

thus, theoretical yield of SO3 is 8.57*10-4 mol

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