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Be sure to answer all parts. Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a...

Be sure to answer all parts.

Consider the reaction 4PH3(g) → P4(g) + 6H2(g)

At a particular point during the reaction, molecular hydrogen is being formed at the rate of 0.149 M/s.

(a) At what rate is P4 being produced?

(b) At what rate is PH3 being consumed?

PLEASE HELP! I WILL RATE LIFESAVER!

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Homework Answers

Answer #1

rate of reaction in terms of all reactant and products are:

rate = (1/4)*rate of consumption of PH3 = rate of production of P4 = (1/6)*rate of production of H2

a)

USE:

rate of production of P4 = (1/6)*rate of production of H2

= (1/6)*0.149 M/s

= 0.0248 M/s

Answer: 0.0248 M/s

b)

(1/4)*rate of consumption of PH3 = (1/6)*rate of production of H2

rate of consumption of PH3 = (4/6)*rate of production of H2

rate of consumption of PH3 = (4/6)*0.149 M/s

= 0.0993 M/s

Answer: 0.0993 M/s

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