An enzyme catalyzes the reaction A -> B +H2O. If km for this reaction is 100uM and vmax is 4umol/min/mg enzyme, calculate the amount of B formed in 2.0 min by 1.0 mg enzyme with 50uM A in solution.
The kinetics of an enzyme catalysed reactions are governed by the Michealis-Menten equation.
where (v) is the rate of reaction and [S] is the substrate (reactant) concentration.
We are given Vmax, Km, and [S]
Vmax = 4 umol/min/mg enzyme or 4 umol/min (since we have 1 mg of enzyme)
Km = 100 umol/L (uM = umol/L)
[S] = 50 umol/L
v = 1.33 umol/min
The rate of reaction means how much substrate is coverted to product per unit time
so [B] after 2 min at a rate of 1.33 umol/min = 2.66 umol
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