Question

A cylinder, with a piston pressing down with a constant pressure, is filled with 2.10 moles of a gas (n1), and its volume is 44.0 L (V1). If 0.600 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

Answer 1

At constant T & P for an Ideal gas, Volume is directly proportional to   the amount of gas i.e. # of moles of gas.

Mathematically,

V n ............ (P & T constant)

V/n = constant

I.e. V1/n1 = V2/n2. ............... (1)

Let initially, When, n1 = 2.10 mole Volume V1 = 44.0 L

After 0.6 mole gas leak out, n2 = 2.10-0.600 = 1.500, Volume V2 = ?

Placing known data in eq.1 we have,

44.0 L / 2.10 mole = V2 / 1.50 mole

V2 = 44.0 L * 1.50 mole / 2.10 mole

V2 = 31.429 L

Final volume of gas in the cylinder is 31.429 L

===================XXXXXXXXXXXXXXXXXXXXXX========================