Question

It is desired to standardize a HCl solution for which 50 ml of HCl are taken and titrated with 29.71 ml of Ba (OH) 2 to reach the end point. Show the equation and determine the molarity of HCl

Answer 1

Given,

Volume of HCl = V1 = 50 mL

Volume of Ba (OH)2 = 29.71 mL

Molarity of HCl = M1

Molarity of Ba (OH)2 = M2

Note: Insufficient data provided in the question. To solve the given question, molarity of Ba (OH)2 is required.

Since, Molarity of Ba (OH)2 is not given,

I am assuming,

Molarity of Ba(OH)2 is, = M2 = 0.03926 M

And we know that, for titration reactions,

M1V1 = M2V2

where, Mi = molarity of substance i

Vi = Volume of substance i

So,

M1V1 = M2V2

==> M1 = M2V2 / V1 = 0.03926 * 29.71 / 50 = 0.0233283 M

Therefore,

Molarity of HCl = 0.02333