Question

# Calculate the quotient [H3PO4]/[H2PO4] in 0.05 M K2HPO4. K1= 7.11x10^-3, K2= 6.32x10^-8, K3=4.17x10^-3​

Calculate the quotient [H3PO4]/[H2PO4] in 0.05 M K2HPO4. K1= 7.11x10^-3, K2= 6.32x10^-8, K3=4.17x10^-3​

#### Homework Answers

Answer #1

HPO42-   ---------------> H+   +   PO43-

0.05                                0            0

0.05 - x                            x             x

ka3 = x^2 / 0.05 - x

4.17 x 10^-13 = x^2 / 0.05 - x

x = 1.44 x 10^-7

[H+] = 1.44 x 10^-7 M

H3PO4   -------------> H+ + H2PO4-

Ka1 = [H+][H2PO4-] / [H3PO4]

7.11 x 10^-3 = [H2PO4-] x 1.44 x 10^-7 / [H3PO4]

[H2PO4-] / [H3PO4] = 49241.6

[H3PO4] / [H2PO4-] = 2.03 x 10^-5

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