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Question 1. Consider the following reaction: A -> B + C. The initial reaction rates corresponding...

Question 1. Consider the following reaction: A -> B + C. The initial reaction rates corresponding to the initial concentrations of 0.110 and 0.220 mol/L were (1x10^-3) mol/(L*s) and 8 times that amount. Determine the order of the reaction. Round your result to the closest whole number

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Answer #1

Solution :-

Given data

exp 1 = Initial concentration = 0.110 mol /L , rate = 1*10-3 mol/(L.s)

exp 2 = initial concentration = 0.220 mol /L , rate = 8 * 1*10-3 mol/(L.s)

order of reaction = ?

lets make the set up to calculate the order of reaction.

(rate 2 / rate1) = ([A]2/[A]1)m

lets put the values in the formula

(8 * 1*10-3 mol per (L.s)) / 1*10-3 mol per (L.s) = ([0.220 mol per L]/[0.110 mol per L])m

8 = (2)m

log 8 = m * log 2

m = log 8 / log 2

m = 3

Therefore order with respect to the reactant A is third order that 3

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