What mass of carbon dioxide is present in 1.00 m3 of dry air at a temperature of 15 ∘C and a pressure of 699 torr ?
V =1m^3 = 1000L
T = 15+273 = 288K
P = 699 torr = 699/760 = 0.9197atm
PV = nRT
n = PV/RT
= 0.9197*1000/0.0821*288 = 38.89moles
mass of CO2 = no of moles * gram molar mass
= 38.89*44 = 1711.16g of Co2 >>>>>answer
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