Question

An X-ray photon with a wavelength of 0.943 nmstrikes a surface. The emitted electron has a kinetic energy of 934 eV. What is the binding energy of the electron in kJ/mol? [Note that KE = 12mv2 and 1 electron volt (eV) = 1.602×10−19J.]

Part A

What is the binding energy of the electron in kJ/mol? [Note that KE = 12mv2 and 1 electron volt (eV) = 1.602×10−19J.]

Answer 1

ans)

from above data that

we know that

Photon Energy = E = h*c/λ

we know that =h= (6.6261e-34)

c=3.0e+8

λ =0.0943e-9

substitue all values in above equation

          = (6.6261e-34)*(3.0e+8)/(0.943e-9)
= 2.11 e-16 Joules

Kinetic Energy Of Emitted Electron = K
          = (934)*(1.602e-19)
          = 1.496e-16 Joules  

Binding Energy Per Electron = E - K
          = (2.11 e-16) - (1.496 e-16)
          = 6.14 e-17 Joules

we have to calculate the

Electron Binding Energy Per Mole

          = (6.14 e-17)*(6.0221e+23)
= 36975 kJ/mole