Question

What are the oxidation numbers for all the elements in the reaction (for both reactants and products, )

2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g).

Answer 1

3C=12 +ve charges
2Fe2 actually means 4Fe ions & so it has 4*3=12 +ve charges
2O3 actually means 6O ions & so it has 6*2=12 -ve charges
So, u see 2Fe2O3 means 12 + & 12 - charge= 0 charge

On right side,
4Fe=12 +ve
3C=12 +ve charges
3O2 means actually 6O ions & so it has 6*2=12 -ve charges
So, u see 3CO2 means 12 + & 12 - charge= 0 charge

So charge remains same on both sides ( a neutral i.e. 0 charge compound & ions with 12 +ve charge) only, charge carrier changes frm C to Fe.