Question

A chemist adds 0.86L of a 9.20/gdL sodium carbonate Na2CO3 solution to a flask.

Calculate the mass in grams of sodium carbonate the chemist has added to the flask. Round your answer to 2 significant digits.

Answer #1

volume = 0.86 L

concentration = 9.20 g / dL

= 92 g/L / 106 g/mol

= 0.868 M

molarity = moles / volume

0.868 = moles / 0.86

moles = 0.746

molar mass of Na2CO3 = 106 g/mol

mass = moles x molar mass

= 0.746 x 106

= 79.12 g

**mass of Na2CO3 = 79 g**

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