Menthol is a crystalline substance with a peppermint taste and odor. When 0.606 g of menthol is dissolved in 25.0 g of cyclohexane, the freezing point of the solution is lowered by 3.23 °C. The freezing point and Kf constant for cyclohexane can be found here. Calculate the molar mass of menthol.
Solvent | Formula | Kf
value*
(°C/m) |
Normal freezing point (°C) |
Kb
value
(°C/m) |
Normal boiling point (°C) |
water | H2O | 1.86 | 0.00 | 0.512 | 100.00 |
benzene | C6H6 | 5.12 | 5.49 | 2.53 | 80.1 |
cyclohexane | C6H12 | 20.8 | 6.59 | 2.92 | 80.7 |
ethanol | C2H6O | 1.99 | –117.3 | 1.22 | 78.4 |
carbon tetrachloride |
CCl4 | 29.8 | –22.9 | 5.03 | 76.8 |
camphor | C10H16O | 37.8 | 176 |
Answer:_____g/mol
Given that mass of menthol w = 0.606 g
molar mass of menthol M = ?
mass of solvent ( cyclohexane ) W = 25 g = 0.025 kg
Kf of cyclohexane = 20.8 oC/m
depression in freezing point dT = 3.23 oC
We know that
depression in freezing point ΔT = Kf x molality
molality = (w/M) x (1/W in kg)
Then, depression in freezing point ΔT = Kf x { (w/M) x (1/W) }
M = (Kf x w ) / (ΔT x W)
= (20.8 oC/m x 0.606 g) / (3.23 oC x 0.025 kg)
= 156
M = 156
Therefore,
molar mass of menthol = 156
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