Complete each of the statements below.
When work is done on a system by its surroundings, the sign of w is [ Select ] ["positive", "negative"] .
When work is done by a system on its surroundings, the sign of w is [ Select ] ["negative", "positive"] .
When q has a negative sign, we can say that heat is transferred [ Select ] ["from", "into"] the system [ Select ] ["from", "into"] its surroundings.
If ∆U for a system is 0 and w is negative, then q must be [ Select ] ["positive", "negative"] .
(1) From Thermodynamics, we know work done on a system by its surrounding, the sign of w is positive.
(2) We now work done by a system on its surrounding , the sign of w is negative.
(3) we know from first law of thermodynamics,
Heat is transferred into the system q > 0
Heat is transferred out of the system � q < 0
In question q is negative so answer will be ["from", into "] its surrounding.
(4) We know from first law of thermodynamics,
∆U = q+w
From question, ∆U = 0 , W = -ve
Put all information from question in abov relationship
0 = q - w
So q = w
So q must be positive
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