Question

Kinetics

For H2 +I2 ->2HI

10^{3}k (1/^{0}Cs)
0.54
2.5
14
25
64

T (K) 599 629 666 683 700

Find E_{a} and A

Answer #1

from the data take first two rate constant values and first two temperatures.

when two tempareture are given the Arrehenius equation

K1-------------- rate constant at T1 temperature (low T) = 0.54

K2-------------- rate constant at T2 temperature (high T) = 2.5

T1= 599K

T2=629K

log(k2/k1) =( Ea/2.303R)[1/T1-1/T2]

log (2.5/0.54) =( Ea/2.303x 8.314 x10^-3)[1/599-1/629]

**Ea= 160 kJ/mol**

another equation

K= A . e ^-Ea/RT

take first rate constant and temperature

0.54 = A . e ^-160/8.314 x10^-3 x599

A= 4.87 x10^{13}

**A= 4.87 x10 ^{13} rate constant
units**

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