Question

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is

2KclO3 ----> 2KCl+3O2

calculate how many grams of O2(g) can be produced from heating 26.3 grams of KClO3 (S)

Answer #1

2 KClO3 ----------------------> 2 KCl + 3O2

245 g 96 g

26.3 g ???

245 g KClO3 ---------------------> 96 g O2

26.3 g KClO3 -----------------------> x g O2

x = 26.3 x 96 / 245

x = 10.3 g

**mass of O2 produced = 10.3 g**

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2KClO3(s) +
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*please explain

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