Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is
2KclO3 ----> 2KCl+3O2
calculate how many grams of O2(g) can be produced from heating 26.3 grams of KClO3 (S)
2 KClO3 ----------------------> 2 KCl + 3O2
245 g 96 g
26.3 g ???
245 g KClO3 ---------------------> 96 g O2
26.3 g KClO3 -----------------------> x g O2
x = 26.3 x 96 / 245
x = 10.3 g
mass of O2 produced = 10.3 g
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