Question

In a particular enzyme-catalyzed reaction, V_max = 0.2 mol/sec and K_m = 5 mM. Assume the enzyme shows standard Michaelis-Menten kinetics. What is the rate of the reaction when [S] = 10mM?

Answer 1

Michaelis–Menten equation is used typically in enzymatic reactions.

V = Vmax*[S] / (Km + [S])

Where

Vmax = max rate velocity

[S] = substrate concentration

Km = Michaelis–Menten constant

V = reaction rate

Michaelis–Menten equation is used typically in enzymatic reactions.

V = Vmax*[S] / (Km + [S])

Where

Vmax = max rate velocity

[S] = substrate concentration

Km = Michaelis–Menten constant

V = reaction rate

then...

if [S] = 10 mM = 10*10^-3 M

and Vmax = 0.2 mol/s, Km = 5mM = 5*10^-3 M

find

V = Vmax*[S] / (Km + [S])

V = 0.2 * (10*10^-3) / (5*10^-3 + 10*10^-3)

V = 0.13333 mol/s