Question

In the following reaction: 3 MgO(s) + 2 Fe(s) → Fe2O3(s) + 3 Mg(s) If you start with 25.0 grams of Fe, how many grams of Mg will you produce?

Answer 1

Balanced Reaction:

3MgO(s) + 2Fe(s) → Fe2O3(s) + 3Mg(s)

Start with 25.0 grams of Fe.

The molar mass of Fe = 55.845 g/mol

Mole of Fe in 25 g = (25 g)/(55.845 g/mol) = 0.448 mol

From a balanced reaction, we can say that 1 mol of Fe in excess MgO produces 1.5 mol of Mg.

0.448 mol of Fe in excess MgO will produce 1.5×0.448 mol of Mg.

Mole of Mg produced = 0.672 mol

The molar mass of Mg is 24.305 g/mol

Mass of Mg in 0.672 mol = (0.672 mol)(24.305 g/mol)

Mass of Mg produced = 16.33 g

( 16.33 g of Mg produced.)