A soil is 75% saturated with Ca+2 + Mg+2 + K+. 50 g of this soil is titrated with 20 ml of 0.1 N NaOH. Calculate the CEC.
CEC(CATION EXCHANGE CAPACITY), reported by nearly all soil testing laboratories, it is a calculated value that is an estimate of the soils ability to attract, retain, and exchange cation elements. It is reported in millequivalents per 100 grams of soil (meq/100g)
Ca++ |
40(at.wt) |
2(valency) |
20 |
(millli equivalents) |
|
Mg++ |
24 |
2 |
12 |
||
K+ |
39 |
1 |
39 |
50 g of this soil is titrated with 20 ml of |
0.1N NaOH Solution |
Cec of the soil is = milliequivalent of NaOH used for sample titration x 100/weight of standard 0.1NaOH(if the solution is prepared for 1000 ml)
= 2x 100/4 =50 milliequivalent/100gm
but the soil sample is 50 gm
therefore the cec is 25 milliequivalent/50gm
Get Answers For Free
Most questions answered within 1 hours.