1. Write the complete nuclear symbol for the antiparticle of a
proton.
2. What is the change in energy when a proton and its antiparticle
collide? (Sign and magnitude are important when you report your
answer.)
3. On a per mole basis, how many times greater is the energy
released
by the reaction described in Part 2 than that released by the
combustion of octane under standard conditions (ΔH°comb
=-5460.0
kJ/mol)?
ans)
a)
antiproton is
(pronounced p-bar)
b)
Energy released when a proton and antiproton anhilates = 1.88 Gev
we know that
Enrgy = 1.88 GeV
= 1.88*10^9 eV= 1.6*10^-19 *1.88*10^9 = 3.008*10^-10 J
c)
Energy released by anhillation of 1 proton = 3.0*10^-10 J
Enrgy released by 1 mol of proton = 6.022*10^23 * 3.0*10^-10 = 1.811*10^14 J
Energy released by combustion reaction =-5460 KJ = -5460000 J
Ratio = 1.811*10^14 / 5460000 = 33.2*10^6 = 33.2 million times
Answer: 33.2 million times
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