Question

determine the entropy change for the displacement reaction represented by the following equation :  Cl2 +...

determine the entropy change for the displacement reaction represented by the following equation : 

Cl2 + PbBr2 -> PbCl2 + Br2 

Cl2 = 223.066 delta S 
PbBr2 = 182.7 delta S 
PbCl2 = 131.3 delta S 
Br2 = 152.231 delta S

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Answer #1

Answer :

Given stoichiometrically balanced displacement reaction,

Cl2 + PbBr2PbCl 2 + Br2.

Entropy change (ΔSrxn) for any reaction is given as,

ΔSrxn = Σ Sf (products) - Σ Sf (reactants)

Hence for above reaction,

ΔSrxn = [Sf (PbCl 2)+Sf (Br2)] - [Sf (Cl2)+Sf (PbBr2)]

Using given values of entropies of species involved we get,

ΔSrxn = [(+152.231)+(+131.300)] - [(+182.700)+(+223.066)]

ΔSrxn = -122.235 J/K.mole

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