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Standard hydrochloric acid (HCl) reagent is 12.0 M. Describe how to prepare 500 mL of 0.100...

Standard hydrochloric acid (HCl) reagent is 12.0 M. Describe how to prepare 500 mL of 0.100 M HCl.

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Answer #1

Molarity = (mass/molarmass)*(1000/V in mL)

According to dilution formula

M1V1 = M2V2

12.0*V1 = 0.100*500

V1 = 4.17 mL

Intially we have to take 4.17 mL of 12.0 M HCl solution and is diluted to 500 ml solution by adding water.

Volume of water added = 500 - 4.17

                                      = 495.83 mL

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