Au3+(aq) + 3e- --> Au(s) |
1.498 V |
Ag+(aq) + e- --> Ag(s) |
0.767 V |
Cu2+(aq) + 2e- --> Cu(s) |
0.342 V |
Ni2+(aq) + 2e- -->Ni(s) |
-0.257 V |
Calculate the potential at 25ºC for the following cell:
Cu | Cu2+ [0.024M] || Ag+ [0.0048M] | Ag
Cu | Cu2+ [0.024M] || Ag+ [0.0048M] | Ag
Cu(s) -------------------> Cu^2+ (aq) +
2e^- E0 = -0.342v
2Ag+(aq) + 2e------------->2 Ag(s) E0 = 0.767v
---------------------------------------------------------------------------------------
Cu(s) + 2Ag^+ (aq) ---------> Cu^2+ (aq) + 2Ag(s) E0 cell = 0.425v
n = 2
Ecell = E0 cell -0.0592/n logQ
= E0 cell -0.0592/n log[Cu^2+]/[Ag^+]^2
= 0.425 -0.0592/2 log0.024/(0.0048)^2
= 0.425-0.0296*3.0177 = 0.34V >>>>answer
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