Question

Ammonia reacts with hypochlorite, OCl −, by the reaction 2 NH3 + 3 OCl − → N2 + 3 Cl − + 3 H2O. What is the molarity of a hypochlorite solution if 1.06 mL of the OCl − solution reacts with 1.80 mg of NH3? ___ M

Answer 1

Number of moles of NH3 = Mass (g)/Molar mass = 0.0018 /17 = 1.06 x 10^-4 mole

Number of moles of ^-OCl reacted = 3/2 x moles of NH3 = 3/2 x 1.06 x 10^-4 mole = 1.59 x 10^-4 mole

Molarity of ^-OCl solution = Number of mole of ^-OCl /Volume of solution (L)

                                    = (1.59 x 10^-4) /(1.06 x 10^-3)

                                    = 0.15 M