Part A
A beaker with 1.60
5.00 - 4.760 = 0.24
10^0.24 =1.74 = [acetate]/ [acetic acid]
[acetate]= 1.74 [acetic acid]
because
[acetate] + [acetic acid]= 0.100
[acetate]= 0.100 - [acetic acid]
0.100 - [acetic acid] = 1.74 [acetic acid]
[acetic acid]= 0.0365 M
[acetate]= 0.100 - 0.0365 = 0.0635 M
moles acetate = 0.160 L x 0.0635 = 0.01016
moles acetic acid = 0.160 L x 0.0365 =0.00584
moles HCl added = 0.00770 L x 0.300 M=0.00231
CH3COO- + H+ = CH3COOH
moles acetic acid = 0.00584 + 0.00231=0.00815
moles acetate = 0.01016 - 0.00231 =0.00785
pH = 4.760 + log 0.00785/ 0.00815 = 4.76 - 0.016 = 4.744
delta pH =5.00 - 4.744 = 0.256
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