Question

What **mass** of **KCl** is required
to make **46 mL** of a **0.10 M KCl
solution**?

____________ g KCl

How many **moles** of
**potassium ions** are present in the solution?

____________ mol

Answer #1

molarity = 0.10 M

volume = 46 mL = 0.046 L

molarity = moles / volume

moles = molarity x volume

= 0.10 x 0.046

= 4.6 x 10^-3

molar mass of KCl = 74.55 g / mol

mass = moles x molar mass

= 4.6 x 10^-3 x 74.55

= 0.343 g

**mass of KCl = 0.34 g**

moles of KCl = 4 .6 x10^-3

**moles of K+ ions = 0.0046**

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