Question

A. What volume of a 2.09M solution of NaClO contains 4.98g of NaClO?

____mL

B. What volume of 0.551M NH₄Br can be prepared from 1.08L of 3.46M NH₄Br?

Your answer should have three significant figures.

______L

Answer 1

A) Number of moles of NaClO = 4.98 g / 74.44 g/mol = 0.0669 mol

Molarity = number of moles / volume of solution in L

2.09 M = 0.0669 / volume of solution in L

volume of solution in L = 0.0669 / 2.09 = 0.0320 L

1L = 1000 mL

0.0320 L = 32.0 mL

Therefore, the volume of solution = 32.0 mL

B) Number of moles of NH4Br = molarity * volume of solution in L

Number of moles of NH4Br = 3.46 * 1.08 = 3.74 mole

Molarity = number of moles / volume of solution in L

0.551 = 3.74 / volume of solution in L

volume of solution = 3.74 / 0.551 = 6.79 L

Therefore, the volume of solution = 6.79 L