A. What volume of a 2.09M solution of NaClO contains 4.98g of NaClO?
____mL
B. What volume of 0.551M NH4Br can be prepared from 1.08L of 3.46M NH4Br?
Your answer should have three significant figures.
______L
A) Number of moles of NaClO = 4.98 g / 74.44 g/mol = 0.0669 mol
Molarity = number of moles / volume of solution in L
2.09 M = 0.0669 / volume of solution in L
volume of solution in L = 0.0669 / 2.09 = 0.0320 L
1L = 1000 mL
0.0320 L = 32.0 mL
Therefore, the volume of solution = 32.0 mL
B) Number of moles of NH4Br = molarity * volume of solution in L
Number of moles of NH4Br = 3.46 * 1.08 = 3.74 mole
Molarity = number of moles / volume of solution in L
0.551 = 3.74 / volume of solution in L
volume of solution = 3.74 / 0.551 = 6.79 L
Therefore, the volume of solution = 6.79 L
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