Question

Calculate Keq for the following reaction.   CO + ½O2 ↔ CO2 Go = -257 kJ /...

Calculate Keq for the following reaction.

  CO + ½O2 ↔ CO2

Go = -257 kJ / mole of CO at 298 K  

Please show all work!

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Answer #1

Solution :-

CO + 1/2O2 --- > CO2

Go = -257 kJ/mol of the CO

Using the Go value we can calculate the K eq

Go = - RT ln K

R= gas constant (8.314 J/mol K)

T= Kelvin temperature

Lets convert the kJ to joules

-257 kJ/mol * (1000 J / 1 kJ) = -257000 J/mol

Now lets use this value in the formula

-257000 J/mol = - 8.314 J/mol K * 298 K * ln Keq

-257000 J/mol / (- 8.314 J/mol K * 298 K) = ln Keq

103.7 = ln Keq

Anti ln [103.7] = Keq

e^(103.7)= Keq

1.09*10^45 = K eq

Therefore the equilibrium constant for the reaction is 1.09*10^45

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