Cadmium, Cd^+2, and cyanide, CN^-, when combined form the complex ion Cd(CN)4^-2. Calculate the concentrations of Cd^+2, CN^- and Cd(CN)4^-2 at equilibrium when 0.50 grams of Cd(NO3)2, dissolves in 500.0 ml of .50M NaCN solution. Please explain why and when to use -x and +x.
Cd^+2 + 4CN^- <-> Cd(CN)4^-2 Kf = 7.1x10^16
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