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What and how to calculate the oxidation state of sulfur in both SF4 and Cs(SF5)-?

What and how to calculate the oxidation state of sulfur in both SF4 and Cs(SF5)-?

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Answer #1

The Oxidation state of Sulfer in Cs(SF5)- is +3, as in the element Caesium is +1 as this being an alkali metal the only oxidation state of Cs is +1, F5 sharing -5 charges as the fluorine atom accepts an electron to form an ion with a single negative charge so the equation looks like

+1(Cs)+3(S)-5(F)=-1

As shown in the above equation to balance out all the changes Sulfur is having an oxidation state of +3. Here the charges of Caesium, Sulfur and Florine are in equal to the overall single negative charge which is mentioned in the equation Cs(SF5)-

Similarly, the Oxidation state of sulfur in SF4 is +4 as the F4 is sharing -4 and to balance it out S is having an oxidation state of +4, which looks like S+4F4-4

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