Question

A U-tube manometer contains two liquids. The first is benzene and the second is water. The differential pressure measures, that is the difference in height between the two liquid interfaces is 36.3 cm. Determine the differential pressure as measured across the manometer tubes in kPa.

Please please show the steps how this problem is done. Ill give the most points to the best answer and best steps shown.

Answer 1

We know that Pressure P = hdg

where h= height

d= density of the liquid

g= accelertaion due to gravity

Given that the difference in height between the two liquid interfaces h = 36.3 cm = 0.363 m

we know that density of benzene d = 876 kg/m^3

acceleration due to gravity g = 9.8 m/s^2

Then substitute the values of h,d, g in the equation P = hdg

Therefore, P = (0.363 m) (876 kg/m^3) (9.8 m/s^2)

= 3116.3 (Kg). (m/s^2).(1/m^2)

= 3116.3 N/m^2 [ since (Kg). (m/s^2) = Newton N ]

= 3116.3 Pa [since N/m^2) = Pascal Pa]

= [3116.3/1000] kPa

= 3.1163 kPa

Therefore, Differential pressure as measured across the manometer tubes = 3.1163 kPa