Question

Use Goal Seek in Excel to calculate [OCl–], [HOCl], [H ], and [OH–] for a 0.0482 M NaOCl solution. The pKa for HOCl is 7.53. Also determine the fraction of OCl- that is hydrolyzed. Ignore activity coefficients.

Answer #1

**[OCl ^{-}] = 0.0482 M**

According to Henderson-Hasselbulch equation:

pH = 7 + 1/2 (pKa + Log[NaOCl])

= 7 + 1/2 (7.53 + Log0.0482)

= 10.11

Now, **[H ^{+}]** = 10

i.e. **[OH ^{-}]** =
10

Therefore, **[HOCl] =** **1.3*10 ^{-4}
M**

The hydrolysis constant, Kh = Kw/Ka =
10^{-14}/10^{-7.53} = 10^{-6.47}

Now, the degree of hydrolysis (h) = (kh/[NaOCl])^{1/2} =
(10^{-6.47}/0.0482)^{1/2} = 0.00265

Therefore, the **percentage of OCl- hydrolyzed** =
0.00265*100 = **0.265%**

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