Question

The number of moles of H2O produced in reaction of 100 mL 1.0 M HCl and 100 mL 1.0 M NaOH

Answer 1

Answer:

HCl + NaOH   NaCl + H₂O

HCl:

V = 100 ML, Molarity (M) = 0.1 M

NaOH:

V = 100 mL, Molarity = 0.1 M

According to the Molarity principle:

M = (moles x 1000) / V in mL

For HCl, 0.1 = (moles x 1000) / 100

0.1 x 100 = moles x 1000

10 = moles x 1000

moles = 10 / 1000

moles = 0.01

For NaOH:  same volume and the concentration same with the HCl

So,

The number of moles = 0.01

HCl + NaOH   NaCl + H₂O

1 1 1 1 moles (According to the equation)

0.01 0.01 ? From the caluculation

From the above the moles of the water is 0.01 (Stoichiometric ratio).