A sample of carbon monoxide gas whose mass is 6.02 g is heated from 25 oC to 156 oC at a constant pressure of 4.86 bar.
Calculate q (in J) for this process.
Calculate w (in J) for this process.
Calculate ΔE (in J) for this process.
mass of CO = 6.02g
Molar mass of CO = 28.009g/mol
No of mole of CO, n= 6.02g/28.009g/mol = 0.21493
work done by system is w
at constant pressure
w= - (n R ∆T )
= - ((0.21493mol)×8.314(J/ K mol) × ( 429.15K - 298.15K))
= - 234.1J
∆E = nCv∆T
Heat capacity of CO, Cv= 20.89(J/ K mol)
∆E = 0.21493mol × 20.89(J/K mol)× (429.15K - 298.15K)
= 588.2J
According to first law of Thermodynamics
∆E = q + w
q = ∆E - w
= 588.2J + 234.1J
= 822.3J
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