What mass of NH4ClO4(molar mass = 117.49 g/mol) is needed to completely react with 20.0 g of aluminum in the reaction: 6 NH4ClO4(s)+ 10 Al(s)3 N2(g)+ 9 H2O(g)+ 5 Al2O3(s)+ 6 HCl(g)
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