Balance the following reaction by the method of half reactions in acidic solution.
SO42 + Br - > Br2 +Se2
SO42- + Br - --------------> Br2 +S02
Half reaction
oxidation state of S in SO42- is +6 and in product wich converted in to +4 i.e. reduction take place.
SO42- --------------> S02
in this two electrons are gained or removol of oxygen i.e reduction hence reaction iss
SO42- + 2e- --------------> S02 + 02 ----------------------1
half reaction
2Br - --------------> Br2 + 2e- -------------------2
from eq 1 and 2
SO42- + 2e- +2Br - --------------> Br2 + 2e- +S02 + 02
SO42- + 2Br - --------------> Br2 + S02 + 02
this is balanced equation
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