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Ethanol (C2H5OH) is synthesized for industrial use by the following reaction, carried out at very high...

Ethanol (C2H5OH) is synthesized for industrial use by the following reaction, carried out at very high pressure. C2H4(g) + H2O(g) C2H5OH(l) What is the maximum amount, in kg, of ethanol that can be produced when 2.35 kg of ethylene (C2H4) and 0.0899 kg of steam are placed into the reaction vessel?

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Answer #1

2.35 kg of ethylene will be 2.35 / 28 = 0.08393 kmol of ehtylene [Molar mass of ehtylene is 28 kg/kmol]

Similarly, 0.0899 kg of steam will be 0.0899/18 =0.005 kmol of steam. According to the reaction, 1 mol of ethylene reacts with 1 mol of steam to give 1 mole ethanol. It can be seen that steam is the limiting reactant for this case and will be reacted completely to give 0.005 kmol of ethanol.

Therefore maximum ethanol that can be produces is 0.005 * 46 = 0.23 kg ethanol

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